C++ 二进制数与八进制数相互转换程序

示例 1：二进制转换为八进制的程序

在此程序中，我们将首先将 二进制数转换为十进制。然后，将十进制数转换为八进制数。

#include <iostream>
#include <cmath>

using namespace std;

int convertBinarytoOctal(long long);
int main()
{
    long long binaryNumber;

    cout << "Enter a binary number: ";
    cin >> binaryNumber;

    cout << binaryNumber << " in binary = " << convertBinarytoOctal(binaryNumber) << " in octal ";

    return 0;
}

int convertBinarytoOctal(long long binaryNumber)
{
    int octalNumber = 0, decimalNumber = 0, i = 0;

    while(binaryNumber != 0)
    {
        decimalNumber += (binaryNumber%10) * pow(2,i);
        ++i;
        binaryNumber/=10;
    }

    i = 1;

    while (decimalNumber != 0)
    {
        octalNumber += (decimalNumber % 8) * i;
        decimalNumber /= 8;
        i *= 10;
    }

    return octalNumber;
}

输出

Enter a binary number: 10001
10001 in binary = 21 in octal

用户输入的二进制数被传递给 convertBinaryToOctal() 函数。该函数将数字转换为八进制数，并返回到 main() 函数。

示例 2：八进制转二进制程序

在此程序中，我们将首先将 八进制数转换为十进制。然后，将十进制数转换为二进制数。

#include <iostream>
#include <cmath>

using namespace std;

long long convertOctalToBinary(int);
int main()
{
    int octalNumber;

    cout << "Enter an octal number: ";
    cin >> octalNumber;

    cout << octalNumber << " in octal = " << convertOctalToBinary(octalNumber) << "in binary";

    return 0;
}

long long convertOctalToBinary(int octalNumber)
{
    int decimalNumber = 0, i = 0;
    long long binaryNumber = 0;

    while(octalNumber != 0)
    {
        decimalNumber += (octalNumber%10) * pow(8,i);
        ++i;
        octalNumber/=10;
    }

    i = 1;

    while (decimalNumber != 0)
    {
        binaryNumber += (decimalNumber % 2) * i;
        decimalNumber /= 2;
        i *= 10;
    }

    return binaryNumber;
}

输出

Enter an octal number: 54
54 in octal = 101100

用户输入的八进制数被传递给 convertOctalToBinary() 函数。该函数将数字转换为二进制数，并返回到 main() 函数。