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此程序要求用户输入noOfRecords的值，并使用malloc()函数为noOfRecords结构变量动态分配内存。
演示结构的动态内存分配
#include <stdio.h>
#include <stdlib.h>
struct course {
int marks;
char subject[30];
};
int main() {
struct course *ptr;
int noOfRecords;
printf("Enter the number of records: ");
scanf("%d", &noOfRecords);
// Memory allocation for noOfRecords structures
ptr = (struct course *)malloc(noOfRecords * sizeof(struct course));
for (int i = 0; i < noOfRecords; ++i) {
printf("Enter subject and marks:\n");
scanf("%s %d", (ptr + i)->subject, &(ptr + i)->marks);
}
printf("Displaying Information:\n");
for (int i = 0; i < noOfRecords; ++i) {
printf("%s\t%d\n", (ptr + i)->subject, (ptr + i)->marks);
}
free(ptr);
return 0;
}输出
Enter the number of records: 2 Enter subject and marks: Science 82 Enter subject and marks: DSA 73 Displaying Information: Science 82 DSA 73