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相加两个复数
#include <stdio.h>
typedef struct complex {
float real;
float imag;
} complex;
complex add(complex n1, complex n2);
int main() {
complex n1, n2, result;
printf("For 1st complex number \n");
printf("Enter the real and imaginary parts: ");
scanf("%f %f", &n1.real, &n1.imag);
printf("\nFor 2nd complex number \n");
printf("Enter the real and imaginary parts: ");
scanf("%f %f", &n2.real, &n2.imag);
result = add(n1, n2);
printf("Sum = %.1f + %.1fi", result.real, result.imag);
return 0;
}
complex add(complex n1, complex n2) {
complex temp;
temp.real = n1.real + n2.real;
temp.imag = n1.imag + n2.imag;
return (temp);
}
输出
For 1st complex number Enter the real and imaginary parts: 2.1 -2.3 For 2nd complex number Enter the real and imaginary parts: 5.6 23.2 Sum = 7.7 + 20.9i
在此程序中，声明了一个名为complex的结构。它有两个成员：real和imag。然后，我们从该结构创建了两个变量n1和n2。
这两个结构变量被传递给add()函数。该函数计算总和并返回包含总和的结构。
最后，从main()函数打印复数的总和。